(1/27)^4-x=9^2x-1

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Solution for (1/27)^4-x=9^2x-1 equation: 



(1/27)^4-x=9^2x-1

We move all terms to the left:

(1/27)^4-x-(9^2x-1)=0

We add all the numbers together, and all the variables

-x-(9^2x-1)+(+1/27)^4=0

We add all the numbers together, and all the variables

-1x-(9^2x-1)+(+1/27)^4=0

We get rid of parentheses

-1x-9^2x+1+(+1/27)^4=0

We multiply all the terms by the denominator


-1x*27)^4-9^2x*27)^4+1*27)^4+(+1=0

Wy multiply elements

-19683x^4=0

We do not support expression: x^4

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